x/2x+2-2x/x^2-2x-3=x/6-2x

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Solution for x/2x+2-2x/x^2-2x-3=x/6-2x equation: 



x/2x+2-2x/x^2-2x-3=x/6-2x

We move all terms to the left:

x/2x+2-2x/x^2-2x-3-(x/6-2x)=0



Domain of the equation: 2x!=0

x!=0/2

x!=0

x∈R





Domain of the equation: x^2!=0

x^2!=0/

x^2!=√0

x!=0

x∈R





Domain of the equation: 6-2x)!=0

We move all terms containing x to the left, all other terms to the right

-2x)!=-6

x!=-6/1

x!=-6

x∈R



We add all the numbers together, and all the variables

x/2x-2x/x^2-2x-(-2x+x/6)+2-3=0

We add all the numbers together, and all the variables

-2x+x/2x-2x/x^2-(-2x+x/6)-1=0

We get rid of parentheses

-2x+x/2x-2x/x^2+2x-x/6-1=0

We calculate fractions

We do not support expression: x^3

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